Statistical Model Shows Putin’s Party Won Just 34% of Real Vote in Russian Elections
Novaya Gazeta Europe said the party’s official 58% result was inflated by fraud, citing a statistical method used by analysts.
5 Articles
5 Articles
Novaya Gazeta Europe: United Russia would have won just 34% in State Duma elections without ballot stuffing
Without fraud, United Russia would have won about 34% of the vote in the State Duma elections. The party’s official result — nearly 58% — was about 1.7 times that figure. Novaya Gazeta Europe reached this conclusion using calculations based on election analyst Sergey Shpilkin’s method.
The Result of Putin's Party in the “Elections” without Falsifications Would Be Almost Twice as Small
The Kremlin falsified the results of the pseudo-elections to the State Duma held on September 18—20. Without fake votes, the result of Putin's United Russia party could have been about 34% instead of the official 57.8%.
This is 1.7 times less than the official result of 57.8% of the vote, according to New Europe. Dozhd TV: news, video, broadcast, online, archive, program program.
On the graph is the result of the identification of electoral anomalies based on the laws of statistics. According to the method developed by physicist Sergei Spilkin, the proportion of real votes can be calculated by knowing the distribution of votes for different parties by appearance and result. The fair polling stations must form a level "core" on such distribution, and the areas with falsifications form the so-called comet tail. This year, …
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